A) 1
B) \[-\text{ }2\]
C) 2
D) \[-\text{ }1\]
Correct Answer: A
Solution :
\[{{(a+b)}^{2}}={{a}^{2}}+{{b}^{2}}+2ab\] \[\Rightarrow \]\[25=13+2ab\] \[\Rightarrow \]\[2ab=25-13=12\] \[\therefore \] \[{{\left( a-b \right)}^{2}}=\text{ }{{a}^{2}}+{{b}^{2}}-2ab\] \[=13-12=1\] \[\Rightarrow \]\[a-b=1\]You need to login to perform this action.
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