A) 53
B) 63
C) 37
D) 45
Correct Answer: A
Solution :
\[\angle\]AEC + \[\angle\]CAD +\[\angle\]DEB = \[{{180}^{{}^\circ }}\] \[\Rightarrow\] \[{{37}^{{}^\circ }}+{{90}^{{}^\circ }}\] + \[\angle\]DEB = \[{{180}^{{}^\circ }}\] \[\Rightarrow\] \[\angle\] DEB = \[180{}^\circ\] - \[127{}^\circ \] = \[53{}^\circ \] \[EB\text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ }CD\] \[\therefore\] \[\angle\]BED =\[\angle\]EDC = \[53{}^\circ \]You need to login to perform this action.
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