A) 32%
B) 35%
C) 28%
D) 30%
Correct Answer: B
Solution :
Let the required gain % = \[x.\] \[\therefore \,\,\,150\times \frac{90}{100}+300\times \frac{(100+x)}{100}=\frac{450\times 120}{100}\] \[\Rightarrow 135+3\,(100+x)=540\] \[\Rightarrow 3\,(100+x)=540-135=405\] \[\therefore \] \[100+x=\frac{405}{3}=135\] \[\Rightarrow x=135-100=35%\]You need to login to perform this action.
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