A) \[1:2\]
B) \[1:1\]
C) \[\sqrt{2}:1\]
D) \[2:1\]
Correct Answer: B
Solution :
OA = OB = r units \[\angle \]AOC = \[30{}^\circ \]; AC = CB In \[\Delta \] AOC, sin \[AOC=\frac{AC}{OA}\] \[\Rightarrow \sin 30{}^\circ =\frac{AC}{r}\] \[\Rightarrow \frac{1}{2}=\frac{AC}{r}\] \[\Rightarrow AC=\frac{r}{2}\] \[\Rightarrow AB=2\times \frac{r}{2}=r\] units \[\therefore \] Required ratio \[=1:1\] \[\] OA = OB \[\therefore \angle OAB=\angle OBA=60{}^\circ \] \[\therefore \Delta \,OAB\] is an equilateral triangle. \[\therefore OA=OB=AB\]You need to login to perform this action.
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