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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-9

  • question_answer
    If sin \[\frac{\pi x}{2}={{x}^{2}}-2x+2\], then the value of \[x\] is

    A) 0                                 

    B) 1

    C) \[-1\]                            

    D) None of these

    Correct Answer: B

    Solution :

    \[\sin \frac{\pi x}{2}={{x}^{2}}-2x+2\] Putting \[x=1\] Sin \[\frac{\pi }{2}=1-2+2=1\]


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