A) 176 ab
B) 276 \[{{a}^{2}}b\]
C) 178 ab
D) 188 \[{{b}^{2}}a\]
Correct Answer: A
Solution :
\[121{{a}^{2}}+64{{b}^{2}}\] \[={{(11a)}^{2}}+{{(8b)}^{2}}\] \[\because \] \[{{(x+y)}^{2}}={{x}^{2}}+{{y}^{2}}+2xy\] \[\therefore \] Required expression \[=2\times 11a\times 8b\] \[=176ab\]You need to login to perform this action.
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