A) 45
B) 48
C) 30
D) 60
Correct Answer: D
Solution :
Part of the tank filled by pipe in 1 hour \[=\frac{1}{10}\] With leakage part filled in 1 hour \[=\frac{1}{12}\] \[\therefore \] Part emptied in 1 hour by leakage \[=\frac{1}{10}-\frac{1}{12}=\frac{6-5}{60}=\frac{1}{60}\] \[\therefore \] Required time = 60 hoursYou need to login to perform this action.
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