A) \[5(a+4)\]
B) \[\frac{abcde}{5}\]
C) \[5\left( a+b+c+d+e \right)\]
D) \[a+4\]
Correct Answer: D
Solution :
Numbers : a, b= a+2 c= a+ 4 d= a+6 e= a+ 8 \[\therefore \] Required average \[=\frac{a+a+2+a+4+a+6+a+8}{5}\] \[=\frac{5a+20}{5}=\frac{5(a+4)}{5}=a+4\]You need to login to perform this action.
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