A) \[9-k\]
B) \[10-k\]
C) \[11-k\]
D) \[k-1\]
Correct Answer: C
Solution :
Let the number be \[10x+y.\] \[\therefore \] \[10x+y=k\,(x+y)\] .... (i) Again, \[10y+x=m(x+y)\] ....(ii) Equations (ii) + (i). \[10x+y+10y+x=(m+k)\,(x+y)\] \[\Rightarrow \] \[11x+11y=(m+k)\,(x+y)\] \[\Rightarrow \] \[11(x+y)=(m+k)\,(x+y)\] \[\Rightarrow \] \[m+k=11\] \[\Rightarrow \] \[m=11-k\]You need to login to perform this action.
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