A) \[10\,kg.\]
B) \[12\,kg.\]
C) \[14\,kg.\]
D) \[16\,kg.\]
Correct Answer: B
Solution :
Let original price of sugar be Rs. x per kg. New price \[=Rs.\left( \frac{120x}{100} \right)=Rs.\left( \frac{6x}{5} \right)per\,kg.\] According to the question, \[\frac{50}{x}-\frac{50}{\frac{6x}{5}}=2\] \[\Rightarrow \] \[\frac{50}{x}-\frac{50\times 5}{6x}=2\] \[\Rightarrow \] \[\frac{50}{x}-\frac{125}{3x}=2\] \[\Rightarrow \] \[\frac{150-125}{3x}=2\] \[\Rightarrow \] \[6x=25\] \[\Rightarrow \] \[x=Rs.\,\,\frac{25}{6}\,kg.\] \[\therefore \] Required quantity of sugar \[=\frac{50}{x}=\frac{50}{\frac{25}{6}}=\frac{50\times 6}{25}=12\,kg.\]
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