A) 1
B) 0
C) -1
D) abc
Correct Answer: A
Solution :
\[a={{(b)}^{p}}\]and \[b={{(c)}^{q}}\] \[\therefore \]\[c={{a}^{r}}={{({{b}^{p}})}^{r}}={{(b)}^{pr}}={{({{c}^{q}})}^{pr}}={{c}^{pqr}}\] \[\Rightarrow \]\[pqr=1\]You need to login to perform this action.
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