A) \[16\,\pi \,c{{m}^{3}}\]
B) \[15\,\pi \,c{{m}^{3}}\]
C) \[\frac{46}{3}\,\pi \,c{{m}^{3}}\]
D) \[\frac{48}{3}\,\pi \,c{{m}^{3}}\]
Correct Answer: C
Solution :
\[\therefore \] Volume \[=\pi {{r}^{2}}{{h}_{1}}+\frac{2}{3}\pi {{r}^{3}}+\pi r_{1}^{2}\times {{h}_{2}}\] \[=\pi (4\times 2+\frac{2}{3}\times 8+1\times 2)\] \[=\pi \,\left( 10+\frac{16}{3} \right)=\frac{46\pi }{3}c{{m}^{3}}\]You need to login to perform this action.
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