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SSC Sample Paper SSC (Group-C) Sample Test Paper-3

  • question_answer
    Sarthak completed a marathon in 4 hours and 35 minutes. The marathon consisted of a 10 km run followed by 20 km cycle ride and the remaining distance again a run. He ran the first stage at 6 km/hr and then cycled at 16 km/hr. How much distance did Sarthak cover in total, if his speed in the last run was just half that of his first run?

    A)  5 km.

    B)  35 km.

    C)  40 km.

    D)  45 km.

    Correct Answer: B

    Solution :

     Let the total distance be x km. Time \[=\frac{\text{Distance}}{Speed}\] According to the question, \[\frac{10}{6}+\frac{20}{16}+\frac{x-30}{3}=4\frac{35}{60}=4\frac{7}{12}\] \[\Rightarrow \] \[\frac{5}{3}+\frac{5}{4}+\frac{x}{3}-10=\frac{55}{12}\] \[\Rightarrow \] \[\frac{x}{3}+\frac{5}{3}+\frac{5}{4}-10=\frac{55}{12}\] \[\Rightarrow \] \[\frac{x}{3}+\left( \frac{20+15-120}{12} \right)=\frac{55}{12}\] \[\Rightarrow \] \[\frac{x}{3}-\frac{85}{12}=\frac{55}{12}\] \[\Rightarrow \] \[\frac{x}{3}=\frac{85}{12}+\frac{55}{12}=\frac{140}{12}\] \[\Rightarrow \] \[x=\frac{140}{12}\times 3=35\,km.\]


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