A) \[\frac{100}{99\times 98\times 97\times ...\times 3\times 2\times 1}\]
B) \[-\frac{1}{99\times 98\times 97\times ...\times 3\times 2\times 1}\]
C) 0
D) \[-\frac{2}{99\times 98\times 97\times ...\times 3\times 2\times 1}\]
Correct Answer: C
Solution :
Expression\[=\frac{(100-1)\,(100-2)(100-3)...(100-100)...(100-200)}{100\times 99\times 98\times ....\times 3\times 2\times 1}=0\]You need to login to perform this action.
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