A) 5
B) \[5\frac{1}{2}\]
C) 6
D) 8
Correct Answer: C
Solution :
Part of work done by Bin 10 days \[=10\times \frac{1}{15}=\frac{2}{3}\] Remaining work \[=1-\frac{2}{3}=\frac{1}{3}\] \[\therefore \] Time taken by \[A=\frac{1}{3}\times 18=6\] daysYou need to login to perform this action.
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