A) 48
B) 64
C) 70
D) 72
Correct Answer: D
Solution :
Relative speed \[=35-25=10\text{ }kmph\]\[=\frac{10\times 5}{18}\,m/\sec .\] Total length \[=80+120=200\]metre \[\therefore \]Required time \[=\frac{Sum\,of\,the\,lengths\,of\,trains}{\text{Rekative}\,\text{speed}}\] \[=\frac{200}{\frac{10\times 5}{18}}=\frac{200\times 18}{10\times 5}\]= 72 seconds
You need to login to perform this action.
You will be redirected in
3 sec
