A) 3
B) 2
C) 4
D) 6
Correct Answer: A
Solution :
Volume of conical vessels \[=\frac{1}{3}\pi {{r}^{2}}h\] \[=\frac{1}{3}\times \pi \times 6\times 6\times 12\] \[=144\,\pi \,cu.cm.\] If the radius of sphere be R cm. then \[8\times \frac{2}{3}\pi {{R}^{3}}=144\pi \] \[\Rightarrow \] \[{{R}^{3}}=\frac{144\times 3}{8\times 2}\] \[=9\times 3=3\times 3\times 3\] \[\therefore \] \[R=\sqrt[3]{3\times 3\times 3}=3cm.\]
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