A) \[\frac{(a-3)}{a}\]
B) \[\frac{1}{3a}\]
C) \[\frac{3a}{(a-3)}\]
D) \[\frac{(a-3)}{3a}\]
Correct Answer: D
Solution :
\[\because \] Dhiru digs \[\frac{1}{a}\] part of field in 20 hours. \[\therefore \] Dhiru digs 1 part of field in 20a hours. Part of field dug by Kaku in 1 hour \[=\frac{1}{60}-\frac{1}{20a}=\frac{a-3}{60a}\] \[\therefore \] Part of field dug by Kaku in 20 hours \[=\frac{20(a-3)}{60a}=\frac{a-3}{3a}\]You need to login to perform this action.
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