A) 68
B) 79
C) 84
D) 92
Correct Answer: C
Solution :
Average of set A \[=\frac{27+28+30+32+33}{5}\] \[=\frac{150}{5}=30\] Case II, New average \[=\frac{30\times 130}{100}=39\] \[\therefore \] \[150+k=39\times 6=234\] \[\Rightarrow \] \[k=234-150=84\]You need to login to perform this action.
You will be redirected in
3 sec