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SSC Sample Paper SSC (Group-C) Sample Test Paper-9

  • question_answer
    Instead of dividing 391 cookies among 3 children A, B , C in the ratio \[\frac{1}{5}:\frac{1}{4}:\frac{1}{8},\] it was divided into the ratio\[5:4:8\]. Who gains the most and how many?

    A)  A, 21 cookies

    B)       B, 78 cookies

    C)  C. 99 cookies

    D)       C, 78 cookies

    Correct Answer: C

    Solution :

     Case I. A.B.C.\[=\frac{1}{5}:\frac{1}{4}:\frac{1}{8}=\left( \frac{1}{5}\times 40 \right):\left( \frac{1}{4}\times 40 \right):\left( \frac{1}{8}\times 40 \right)\] LCM of 5, 4 and 8 =401 \[=8:10:5\] Sum of the terms of ratio                         \[=8+10+5=23\] Case II.             \[A:B:C=5:4:8\] Sum of the terms of ratio \[=5+4+8=17\] Clearly C gains. C's profit \[=\left( \frac{8}{17}-\frac{5}{23} \right)\times 391\] \[=\frac{8}{17}\times 391-\frac{5}{23}\times 391\] \[=184-85=99\]cookies


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