A) A, 21 cookies
B) B, 78 cookies
C) C. 99 cookies
D) C, 78 cookies
Correct Answer: C
Solution :
Case I. A.B.C.\[=\frac{1}{5}:\frac{1}{4}:\frac{1}{8}=\left( \frac{1}{5}\times 40 \right):\left( \frac{1}{4}\times 40 \right):\left( \frac{1}{8}\times 40 \right)\] LCM of 5, 4 and 8 =401 \[=8:10:5\] Sum of the terms of ratio \[=8+10+5=23\] Case II. \[A:B:C=5:4:8\] Sum of the terms of ratio \[=5+4+8=17\] Clearly C gains. C's profit \[=\left( \frac{8}{17}-\frac{5}{23} \right)\times 391\] \[=\frac{8}{17}\times 391-\frac{5}{23}\times 391\] \[=184-85=99\]cookiesYou need to login to perform this action.
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