A) 0
B) 1
C) 10
D) +RT
Correct Answer: B
Solution :
| [b] \[{{\Delta }_{r}}{{G}^{o}}={{\Delta }_{r}}{{H}^{o}}-T\cdot {{\Delta }_{r}}{{S}^{o}}\] |
| \[=-30+300\times 0.1=0\] |
| \[{{\Delta }_{r}}{{G}^{o}}=-2.303\,RT\,\,\log \,K\] |
| \[K=1\] |
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