A) \[\left[ {{I}_{2(g)}} \right]>\left[ I_{(g)}^{-} \right]\]
B) \[\left[ {{I}_{2(g)}} \right]<\left[ I_{(g)}^{-} \right]\]
C) \[\left[ {{I}_{2(g)}} \right]=\left[ I_{(g)}^{-} \right]\]
D) \[\left[ {{I}_{2(g)}} \right]=1/2\left[ I_{(g)}^{-} \right]\]
Correct Answer: A
Solution :
[a] \[{{I}_{2}}\rightleftharpoons 2{{I}^{-}}\] \[{{K}_{c}}={{10}^{-6}}=\frac{4{{x}^{2}}}{\left( 1-x \right)}\] Find x and see \[2x<\left( 1-x \right)\].
You need to login to perform this action.
You will be redirected in
3 sec
