A) \[{{10}^{-4}}\]
B) \[2\times {{10}^{-4}}\]
C) \[4\times {{10}^{-4}}\]
D) \[8\times {{10}^{-4}}\]
Correct Answer: B
Solution :
[b] \[\underset{n}{\mathop{A}}\,\underset{\approx y}{\mathop{\underset{0.5-x}{\mathop{(g)}}\,}}\,+2B\underset{\approx 2y}{\mathop{\underset{1-2x}{\mathop{(g)}}\,}}\,C\underset{\approx 1}{\mathop{\underset{0.5+x}{\mathop{(g)+D}}\,}}\,\underset{\approx 4}{\mathop{\underset{3.5+x}{\mathop{(g)}}\,}}\,\] (due to very high value of equilibrium constant) \[{{10}^{12}}=\frac{1\times 4}{y\times {{(2y)}^{2}}};y={{10}^{-4}};[B(g)]=2y\Rightarrow 2\times {{10}^{-4}}\]You need to login to perform this action.
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