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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Chemical Equilibrium

  • question_answer
    One mole of a compound AB reacts with one mole of a compound CD according to the equation \[A{{B}_{(g)}}+C{{D}_{(g)}}A{{D}_{(g)}}+C{{B}_{(g)}}.\]When equilibrium had been established it was found that 3/4 mole each of reactants AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

    A) 9/16

    B) 1/9     

    C) 16/9

    D) 9

    Correct Answer: D

    Solution :

    [d]
                   \[AB+CDAD+CB\]
    Initially (moles ) 1 1 0 0
    At equilibrium \[1-\frac{3}{4}=\frac{1}{4}\] \[1-\frac{3}{4}=\frac{1}{4}\] \[\frac{3}{4}\] \[\frac{3}{4}\]
    \[K=\frac{[AD][CB]}{[AB][CD]}=\frac{\frac{3}{4}\times \frac{3}{4}}{\frac{1}{4}\times \frac{1}{4}}=9\]


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