A) \[\frac{2}{9}\]
B) \[\frac{4}{9}\]
C) \[\frac{3}{9}\]
D) \[\frac{1}{9}\]
Correct Answer: D
Solution :
[d] \[N{{H}_{2}}CON{{H}_{4}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] |
Let, partial pressure of \[C{{O}_{2}}=p\] |
Then, \[{{p}_{N{{H}_{3}}}}=2p\] |
Total pressure at equilibrium \[=2p+p=3p\] |
\[{{K}_{p}}={{(2p)}^{2}}\times p=4{{p}^{3}}\] |
After addition of \[N{{H}_{3}}\]pressure of \[N{{H}_{3}}=2\times 3p=6p\] |
\[{{K}_{p}}={{({{p}_{N{{H}_{3}}}})}^{2}}\times p{{'}_{C{{O}_{2}}}}\] |
\[4{{p}^{3}}={{(6p)}^{2}}\times p{{'}_{C{{O}_{2}}}}\] |
\[p{{'}_{C{{O}_{2}}}}=\frac{1}{9}p\] \[\frac{p{{'}_{C{{O}_{2}}}}}{{{p}_{C{{O}_{2}}}}}=\frac{1}{9}\] |
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