A) 9/16
B) 1/9
C) 16/9
D) 9
Correct Answer: D
Solution :
[d]\[AB+CDAD+CB\] | ||||
Initially (moles ) | 1 | 1 | 0 | 0 |
At equilibrium | \[1-\frac{3}{4}=\frac{1}{4}\] | \[1-\frac{3}{4}=\frac{1}{4}\] | \[\frac{3}{4}\] | \[\frac{3}{4}\] |
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