JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Sample Paper Topic Test - Chemical Kinetics

  • question_answer
    For the reaction \[A+2B\to \] products(started with concentrations taken in stoichiometric proportion), the experimentally determined rate law is \[-\frac{d[B]}{dt}=k\sqrt{[A]}\sqrt{[B]}\]
    The half time of the reaction would be

    A) \[\frac{\sqrt{2}\times 0.693}{k}\]            

    B) \[\frac{0.693}{1/k}\]

    C) \[\frac{0.693}{\sqrt{2}k}\]                     

    D) not defined

    Correct Answer: A

    Solution :

     A + 2B\[\xrightarrow{{}}\]Product
    a 2a 0
    a - x 2a - 2x x
    \[\therefore \]      \[r=k\,\,\sqrt{A}\,\,\,\sqrt{B}\] \[=\sqrt{(a-x)}\sqrt{2a-2x}\] \[=\sqrt{2}\,k(a-x)\] Solve it for \[{{t}_{1/2}}\]         

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