A) 6.32
B) 5.58
C) 4.11
D) 8.33
Correct Answer: C
Solution :
\[{{t}_{1}}=\frac{2.303}{K}\log \left( \frac{100}{40} \right)\] (i) \[{{t}_{2}}=\frac{2.303}{K}\log \left( \frac{100}{80} \right)\] .....(ii) From (i) and (ii), \[\frac{{{t}_{1}}}{{{t}_{2}}}=4.11\]You need to login to perform this action.
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