JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Sample Paper Topic Test - Electrochemistry

  • question_answer
    Molar conductance's of \[BaC{{l}_{2}},{{H}_{2}}S{{O}_{4}}\] and HCl at infinite dilutions are \[{{x}_{1}},{{x}_{2}}\] and \[{{x}_{3}}\] respectively. Equivalent conductance of \[BaS{{O}_{4}}\] at infinite dilution will be:

    A) \[({{x}_{1}}+{{x}_{2}}-{{x}_{3}})/2\]

    B) \[{{x}_{1}}+{{x}_{2}}-2{{x}_{3}}\]

    C) \[({{x}_{1}}-{{x}_{2}}-{{x}_{3}})/2\]

    D) \[({{x}_{1}}+{{x}_{2}}-2{{x}_{3}})/2\]

    Correct Answer: D

    Solution :

    [d] \[\lambda _{m}^{\infty }(BaS{{O}_{4}})=\lambda _{B{{a}^{2+}}}^{\infty }+\lambda _{SO_{4}^{2-}}^{\infty }\]
    \[=\lambda _{m}^{\infty }(BaC{{l}_{2}})=\lambda _{m}^{\infty }{{({{H}_{2}}S{{O}_{4}})}^{-}}-2\lambda _{(HCl)}^{\infty }\]
    \[={{x}_{1}}+{{x}_{2}}-2{{x}_{3}};\,\lambda _{e}^{o}\frac{1}{2}\lambda _{m}^{\infty }(BaS{{O}_{4}})\]


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