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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Sample Paper Topic Test - Electrochemistry

  • question_answer
    The resistance of 0.1N acetic acid when measured in a cell with cell constant \[1.5\,c{{m}^{-1}}\] is \[5.250\,\Omega \]. The value of \[{{\lambda }_{eq}}\] of \[0.1\,N\,AcOH\] is

    A) 60

    B) 90

    C) 18.4

    D)  0.023    

    Correct Answer: A

    Solution :

    [a] \[{{\Lambda }_{eq}}=k\times 1000/N\]
    Now,  \[k=1.5/250,\]
    \[\therefore \] \[{{\Lambda }_{eq}}=(1.5/250)\times 1000/0.1=60{{\Omega }^{-1}}c{{m}^{2}}e{{q}^{-1}}\]


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