JEE Main & Advanced Physics NLM, Friction, Circular Motion Sample Paper Topic Test - Friction

  • question_answer
    Car is accelerating with acceleration = 20 m/s2. A box of mass m = 10 kg that is placed inside the car it is put in contact with the vertical wall of car as shown. The friction coefficient between the box and the wall is \[\mu =0.6\].

    A) The acceleration of the box will be \[10\,m/{{\sec }^{2}}\]

    B) The friction force acting on the box will be 100 N

    C) The contact force between the vertical wall and the box will be 100 N

    D) None of these

    Correct Answer: B

    Solution :

    The breaking force is insufficient, so the block will not slide.    
    So friction force = 100 N                                               
    and acceleration will be \[20\,m/{{\sec }^{2}}\]only                                   
    Net contact force on the block
    \[=\sqrt{{{\left( 200 \right)}^{2}}+{{\left( 100 \right)}^{2}}}\,=\,100\sqrt{5\,}\,N\] 

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