| With reference to the figure shown, if the coefficient of friction at the surfaces is 0.42, then the force F required to pull out the 6.0 kg block with an acceleration of 1.50 \[m\text{/}{{s}^{2}}\] will be: |
 |
A) 36 N
B) 24 N
C) 84 N
D) 51 N
Correct Answer: D
Solution :
| \[F-8\left( 0.42 \right)\left( 10 \right)-2\left( 0.42 \right)\left( 10 \right)=6\left( 1.5 \right)\] |
| \[F-42=9\] |
| \[F=51\,\,N\] |
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