JEE Main & Advanced Physics NLM, Friction, Circular Motion Sample Paper Topic Test - Friction

  • question_answer
    A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force F. If \[\mu \]is the coefficient of friction between his palms and the pole, the acceleration with which he slides down is

    A) \[g\]                              

    B) \[\frac{\mu F}{m}\]

    C) \[g+\frac{\mu F}{m}\]               

    D) \[g-\frac{\mu F}{m}\]

    Correct Answer: D

    Solution :

    Here, normal contact force \[N=F\] and friction force, \[f=\mu N\]
    So the free body diagram of boy is as shown adjacent in the above figure.
    Now, \[ma=mg-f\]
    \[\Rightarrow \]   \[a=g-\frac{\mu F}{m}\]

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