The member OA rotates about a horizontal axis through O with a constant counter clockwise velocity \[\omega =3\] \[\text{rad}/\text{sec}\]. As it passes the position\[\theta ={{0}^{o}}\], a small mass m is placed upon it at a radial distance r = 0.5 m. If the mass is observed to slip at \[\theta ={{37}^{o}}\], the coefficient of friction between the mass & the member is: |
A) \[\frac{3}{16}\]
B) \[\frac{9}{16}\]
C) \[\frac{4}{9}\]
D) \[\frac{5}{9}\]
Correct Answer: A
Solution :
As the mass is at the verge of slipping |
\[\therefore \] \[mg\sin 37-\mu \,mg\cos 37=m{{\omega }^{2}}r\] |
\[6-8\mu =4.5\] |
\[\therefore \] \[\mu =\frac{3}{16}\] |
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