List I | List II |
[A] pH of 0.1 M HA \[(p{{K}_{a}}=5)\] and 0.01 M NaA | (p) 4 |
[B] pH of 0.1 M BOH \[(p{{K}_{b}}=6)\] and 0.1 M BCI | (q) 7 |
[C] pH of 0.1 M salt of HA \[(p{{K}_{a}}=5)\] and BOH \[(p{{K}_{b}}=7)\] | (r) 6 |
[D] pH of 500 litre of 0.2 M \[HN{{O}_{3}}\] and 500 litre 0.2 M NaOH | (s) 8 |
A) A\[\to \]p, B\[\to \]s, C\[\to \]r, D\[\to \]q
B) A\[\to \]s, B\[\to \]p, C\[\to \]r, D\[\to \]q
C) A\[\to \]p, B\[\to \]r, C\[\to \]s, D\[\to \]q
D) A\[\to \]p, B\[\to \]s, C\[\to \]q, D\[\to \]r
Correct Answer: A
Solution :
[a] \[pH=p{{K}_{a}}+{{\log }_{10}}\left[ \frac{\text{Salt}}{\text{Acid}} \right]=\]\[5+{{\log }_{10}}\left[ \frac{0.1}{0.01} \right]=4\] |
[b] \[pOH=p{{K}_{b}}+{{\log }_{10}}\left[ \frac{0.1}{0.1} \right]=6\] |
\[pH=14-6=8\] |
[c] \[pH=\frac{1}{2}[p{{K}_{w}}+p{{K}_{a}}-p{{K}_{b}}]=\] |
\[\frac{1}{2}[14+5-7]=6\] |
[d] Neutral solution \[pH=7\] |
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