JEE Main & Advanced Physics Kinetic Theory of Gases Sample Paper Topic Test - Kinetic Theory of Gases

  • question_answer
    The molecules of a given mass of gas have a \[rms\] velocity of 200 m/s at \[{{27}^{o}}C\] and \[1.0\times {{10}^{5}}\,N/{{m}^{2}}\] pressure. When the temperature is \[127{}^\circ C\] and pressure is \[0.5\times {{10}^{5}}\,N/{{m}^{2}},\] the \[rms\] velocity in m/s will be

    A) \[\frac{100\sqrt{2}}{3}\]

    B) \[100\sqrt{2}\]

    C) \[\frac{400}{\sqrt{3}}\]

    D)  None of these

    Correct Answer: C

    Solution :

    [c] Change in pressure will not affect the \[rms\] velocity of molecules. So we will calculate only the effect of temperature.
                As        \[{{v}_{rms}}\propto \sqrt{T}\] 
                \[\therefore \]    \[\frac{{{v}_{{{300}^{0}}}}}{{{v}_{{{400}^{0}}}}}=\sqrt{\frac{300}{400}}=\sqrt{\frac{3}{4}}\Rightarrow \,\frac{200}{{{v}_{{{400}^{0}}}}}=\sqrt{\frac{3}{4}}\]
                \[\Rightarrow \]            \[{{v}_{{{400}^{0}}}}=\frac{200\times 2}{\sqrt{3}}=\frac{400}{\sqrt{3}}\,m/s\]


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