A) \[({{V}_{1}}+{{V}_{2}})/2\]
B) \[{{V}_{1}}\]
C) \[{{({{V}_{1}}{{V}_{2}})}^{1/2}}\]
D) \[\sqrt{3kT/M}\]
Correct Answer: B
Solution :
[b] Average speed of gas molecule \[{{v}_{av}}=\sqrt{\frac{8kT}{\pi m}}\]. It depends on temperature and molecular mass. |
So the average speed of oxygen will be same in vessel A and vessel C and that is equal to \[{{V}_{1}}\]. |
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