A) \[g/n\]
B) \[g/{{n}^{2}}\]
C) \[g/2{{n}^{2}}\]
D) \[g/4{{n}^{2}}\]
Correct Answer: C
Solution :
[c] Time taken by each ball to reach the-highest point is \[t=1/ns\] |
As the juggler throws second ball, when the first ball is at its highest point, so \[v=0\] |
Using \[v=u+at,\] we have \[0=u-g\times 1/n\] |
\[\Rightarrow \] \[u~=g/n\] |
Also \[{{v}^{2}}={{u}^{2}}+2as\] |
\[0={{(g/n)}^{2}}+2(-g)\times h\] |
or \[h=\frac{g}{2{{n}^{2}}}\] |
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