A) V
B) Cr
C) Mn
D) Fe
Correct Answer: B
Solution :
[b] |
\[F{{e}^{+}}(26)=[Ar]\text{ }3{{d}^{6}},\,\,4{{s}^{1}}\] |
\[M{{n}^{+}}\text{(}25\text{)}=[Ar]3{{d}^{5}}\text{ }4{{s}^{1}}\] |
\[{{V}^{+}}\text{(}23\text{)}=[Ar]\text{ }3{{d}^{2}}\text{ }4{{s}^{2}}\] |
\[C{{r}^{+}}\text{(}24\text{)}=[Ar]\text{ }3{{d}^{5}}\text{ }4{{s}^{0}}\] |
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