A) II, III in hematite and II in magnetite
B) II, III in hematite and II in magnetite
C) II in hematite and II, II in magnetite
D) III in hematite and II, III in magnetite
Correct Answer: D
Solution :
[d] Hematite: \[\theta ={{180}^{0}},\] Magnetite: \[\underset{\text{mixed oxide}}{\mathop{F{{e}_{3}}{{O}_{4}}}}\,\to F{{e}_{2}}{{O}_{3}}(+3)+FeO(+2)\]You need to login to perform this action.
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