2. Sample Papers
  3. JEE Main & Advanced
  4. Chemistry
  5. Redox Reactions / रेडॉक्स अभिक्रियाएँ

JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Sample Paper Topic Test - Redox Reactions

  • question_answer
    One mole of \[{{X}_{2}}{{H}_{4}}\] releases 10 moles of electrons to form a compound y. What should be the oxidation number of x in the compound y.

    A) + 3

    B) - 3

    C) - 6

    D) + 1

    Correct Answer: A

    Solution :

    [a] \[{{x}_{2}}{{H}_{4}}-10{{e}^{-}}\to {{({{X}_{2}}{{H}_{4}})}^{+10}}\] \[2x+4=+10\] \[\Rightarrow \]   \[2x=10-4=6x=+3\]


You need to login to perform this action.
You will be redirected in 3 sec spinner