A) \[{{S}_{8}}<{{S}_{2}}O_{8}^{-2}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}\]
B) \[{{S}_{2}}O_{8}^{-2}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}<{{S}_{8}}\]
C) \[{{S}_{2}}O_{8}^{-2}<{{S}_{8}}<{{S}_{4}}O_{6}^{-2}<{{S}_{2}}O_{3}^{-2}\]
D) \[{{S}_{8}}<{{S}_{2}}O_{3}^{-2}<{{S}_{4}}O_{6}^{-2}<{{S}_{2}}O_{8}^{-2}\]
Correct Answer: D
Solution :
[d] The oxidation number of S are shown below along with the compounds \[\underset{0}{\mathop{{{S}_{8}}}}\,,\underset{+6}{\mathop{\text{ }{{S}_{2}}{{O}_{8}}^{-2}}}\,,\underset{+2}{\mathop{\text{ }{{S}_{2}}{{O}_{3}}^{-2},}}\,\underset{+2.5}{\mathop{\text{ }{{S}_{4}}{{O}_{6}}^{-2}}}\,\] Hence the order of increasing O.N. of S is \[{{S}_{8}}<{{S}_{2}}{{O}_{3}}^{-2}<{{S}_{4}}{{O}_{6}}^{-2}<{{S}_{2}}{{O}_{8}}^{-2}\]You need to login to perform this action.
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