A) 5
B) 7
C) 3
D) 8
Correct Answer: C
Solution :
[c]For mirror \[\frac{1}{v}+\frac{1}{-2}=\frac{3}{-4}\]\[\Rightarrow \]\[v=-\,4\]. This is at \[{{I}_{1}}\]. |
Image \[{{I}_{2}}\] is formed by plane mirror which coincides with \[{{I}_{1}}\] |
From the figure it is \[2x=2\] |
\[\sqrt{\frac{h}{g}-\frac{{{P}_{0}}}{\rho {{g}^{2}}}}\] \[x=1\,cm\] |
\[{{P}_{0}}\] thickness \[=\,3\,cm\] |
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