A) \[{{A}_{3}}{{B}_{2}}{{O}_{4}}\]
B) \[{{A}_{2}}{{B}_{2}}{{O}_{4}}\]
C) \[A{{B}_{2}}{{O}_{5}}\]
D) \[A{{B}_{2}}{{O}_{4}}\]
Correct Answer: D
Solution :
| [d] Let number of oxides \[=x\] |
| Number of octahedral void \[=x\] |
| Number of tetrahedral void \[=2x\] |
| Number of \[{{A}^{2+}}\] ion \[=\frac{1}{8}.2x=\frac{x}{4}\] |
| Number of \[{{B}^{3+}}\] ion \[=\frac{x}{2}\] |
| \[\begin{matrix} {{A}^{2+}}: & {{B}^{3+}}: & {{O}^{2-}} \\ \frac{x}{4}: & \frac{x}{2}: & x \\ 1 & 2 & 4 \\ \end{matrix}\] |
| Hence, formula of oxide is \[A{{B}_{2}}{{O}_{4}}\]. |
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