JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

  • question_answer
    The vapour pressure of pure liquid solvent A is atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. What is the mole fraction of component B in the solution?

    A) 0.75

    B) 0.25

    C) 0.40

    D) 0.60

    Correct Answer: B

    Solution :

    [b] \[p={{X}_{A}}{{p}^{o}}\cdot {{X}_{A}}=\frac{p}{{{p}^{o}}}=\frac{0.60\,\text{atm}}{0.80\,\text{atm}}=0.75\]
    \[{{X}_{B}}=1-0.75=0.25\]


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