s Sample papers for JEE Main & Advanced Chemistry Solutions / विलयन Topic Test - Solutions - Studyadda.com
  2. Sample Papers
  3. JEE Main & Advanced
  4. Chemistry
  5. Solutions / विलयन

JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

  • question_answer
    The relative lowering of vapour pressure of aqueous solution containing a non-volatile solute is 0.0125. The molality of the solution is

    A) 0.70

    B) 0.50

    C) 0.80

    D) 0.40

    Correct Answer: A

    Solution :

    [a] \[\frac{p{}^\circ -p}{p{}^\circ }={{X}_{1}}=0.0125=\] mole fraction of solute
    Mole fraction and molarity are related as
    \[\frac{1}{X}-1=\frac{1000}{M\times m}\]
    \[\frac{1}{0.0125}-1=\frac{1000}{18\times m}\]
    \[m=0.70\]


You need to login to perform this action.
You will be redirected in 3 sec spinner