A) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}C{{l}_{3}} \right]Cl\]
B) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}Cl \right]C{{l}_{2}}\]
C) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}C{{l}_{2}} \right]C{{l}_{3}}\]
D) \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}C{{l}_{4}} \right]\]
Correct Answer: B
Solution :
[b] \[\Delta {{T}_{f}}=im{{K}_{f}};\,0.0054=i\times 1.8\times 0.001\] \[i=3.\] So it is \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}Cl \right]C{{l}_{2}}\].
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