JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

  • question_answer
    Suppose 5 gm of \[C{{H}_{3}}COOH\] is dissolved in one litre of ethanol. Assume that no reaction between them takes place. Calculate molality of resulting solution if density of ethanol is 0.789 gm/ml.

    A) 0.0856

    B) 0.0956

    C) 0.1056

    D) 0.1156

    Correct Answer: C

    Solution :

    [c] Weight of \[C{{H}_{3}}COOH\] dissolved = 5 g
    Eq. of \[C{{H}_{3}}COOH\] dissolved \[=\frac{5}{60}\]
    Volume of ethanol = 1 litre = 1000 ml.
    \[\therefore \] Weight of ethanol =1000\[\times \]0.789 = 789 g
    \[\therefore \] Molality of solution\[=\frac{\text{Moles}\,\text{of}\,\text{solute}}{\text{Weight}\,\text{of}\,\text{solvent}\,\text{in}}\]
    \[=\frac{\frac{5}{60\times 789}}{1000}=0.1056\]


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