JEE Main & Advanced Chemistry Solutions / विलयन Sample Paper Topic Test - Solutions

  • question_answer
    Formation of a solution from two components can be considered as
    (i) Pure solvent \[\to \] separated solvent molecules, \[\Delta {{H}_{1}}\]
    (ii) Pure solute \[\to \] separated solute molecules, \[\Delta {{H}_{2}}\]
    (iii) Separated solvent & solute molecules \[\to \] Solution, \[\Delta {{H}_{3}}\] solution so formed will be ideal if

    A) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{3}}-\Delta {{H}_{1}}-\Delta {{H}_{2}}\]

    B) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}\]

    C) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}-\Delta {{H}_{3}}\]

    D) \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}-\Delta {{H}_{2}}-\Delta {{H}_{3}}\]

    Correct Answer: B

    Solution :

    [b] For an ideal solution, \[\Delta {{H}_{mixing}}=0\]
    \[\Delta H=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}\]
    (According to Hess's law)
    i.e., for ideal solutions there is no change in magnitude of the attractive forces in the two components present.


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